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Wednesday, January 28, 2015

Bode Plot of Magnitude

Q: How can I graphically depict ratio of output to input power for a LTI system?
A: Suppose the following:

We could examine \frac{P_o}{P_i}
Alternatively, we could examine log(\frac{P_o}{P_i}) which has dimensionless units of bels
More commonly, we use 10log(\frac{P_o}{P_i}) which gives us decibels (dB)

Let's take a closer look at this 10log(\frac{P_o}{P_i}):
P_i=\frac{1}{2}Re\left\{V_iI_i^*\right\}
P_i=\frac{1}{2}Re\left\{\frac{V_iV_i^*}{R}\right\}
P_i=\frac{1}{2}Re\left\{\frac{|V_i|^2}{R}\right\}
P_i=\frac{|V_i|^2}{2R}

Similarly,
P_o=\frac{|V_o|^2}{2R}

Hence, 10log\frac{P_o}{P_i} =
=10log\frac{|V_o|^2}{|V_i|^2} 
=20log\frac{|V_o|}{|V_i|} 

Recall that |H(j\omega)|=\frac{|V_o|}{|V_i|}
So 10log(\frac{P_o}{P_i})=20log|H(j\omega)|

To visualize the ratio of power with respect to angular frequency, \omega sits on the horizontal axis using a logarithmic scale while 20log|H(j\omega)| sits on the vertical axis. From these 2 axes, a Bode plot may be constructed. For a rough and quick idea of the circuits behavior, straight line approximations are commonly used.

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