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Monday, January 5, 2015

Complex Conjugates

Given: z = a + jb = |z|e^{j\theta}

Q1: What is the complex conjugate of z in Cartesian form?
A1: z^* = a - jb

Q2: What is the complex conjugate of z in polar form?
A2: Note that z^* is simply the reflection of z over the real axis of the complex plane. It then follows that:
1.The magnitude of z^* is the same as the magnitude of z
2. The angle that z^* makes with respect to the positive real axis is the negative value of the angle that z makes with the positive real axis. 
Hence, z^*= |z|e^{-j\theta}

Q3: How can you simplify the expression zz^*?
A3: Although the multiplication suggests that you use polar form to simplify the product, Cartesian form yields an interesting result.
zz^*=(a+jb)(a-jb)
Notice that the cross-terms (i.e. the O and I products of FOIL) negate each other.
zz^*=a^2+b^2
zz^*={|z|}^2

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